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using (4) and the fact that: Total channel cap.

for R (=avg #bad frames) and 1 good one is

(5)

U

=

D

(

L

/

(

1

-

L

)

)

(

F

+

CT

)

+

(

F

+

A

+

2

CI

)

if the variance of I is low then

(6)

subst (6) into (5) gives:

(6a)

U

=

D

(

L

/

(

1

-

L

)

)

(

F

+

A

+

2

CI

)

+

(

F

+

A

+

2

CI

)

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