PP Presentation
(3b)
proof:
(3a)
k
=
1
L
k
=
1
k
=
1
subst. (3b) into (3a)
(3c)
1
L
kL
k
-
kL
k
k
=
1
¥
å
k
=
1
¥
å
=
1
L
L
(
L
-
1
)
2
-
L
(
L
-
1
)
2
=
1
-
L
(
L
-
1
)
2
=
1
1
-
L
Q.E.D.
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